BLOG THREE - SUBNETTING HOMEWORK
A company has a 190.240.0.0/16 block. They now want to re-organise it into large blocks. They wish to have subnets that can handle at least 1000 hosts each.
Also, please calculate the following for the second subnet:
·
Subnet mask
·
Subnet address
·
First usable address in that subnet
·
Last usable address in that subnet
·
Broadcast address of that subnet
|
|
190.240.0.0 / 16 |
|
190
: 240 : SSSSSSHH : HHHHHHHH |
|
|
2S = 64
Subnets :: 256 / 64 = 4 |
4 Subnet Range |
|
2H = 1024 ::
Usable 1024 – 2 |
Number of usable hosts per
subnet |
|
CIDR: |
22 |
|
Number of Subnets: |
64 |
|
Usable Hosts Per Subnet: |
1022 |
|
11111111
. 11111111 . 11111100 . 00000000 |
|
|
Subnet Mask: |
255.255.252.0 |
|
Second Subnet: |
190.240.4.0 |
|
Second Subnet |
|
|
Broadcast Addresses: |
190.240.7.255 |
NMIT has an Internet address of 202.49.18.0 /24. TALOS has
been given a 202.49.18.0/26 subnet.
·
What is the subnet addresses of each of the /26
subnets that NMIT can give out?
·
How many external IP addresses (the maximum in
its subnet) could TALOS use on its firewall?
|
|
202.49.18.0 / 24 |
|
202
: 49 : 18 : SSHHHHHH |
|
|
2S = 4
Subnets :: 256 / 4 = 64 |
4 Subnet Range |
|
2H = 64 ::
Usable 64 – 2 = 62 |
Number of usable hosts per
subnet |
|
CIDR: |
26 |
|
Number of Subnets: |
4 |
|
Usable Hosts Per Subnet: |
62 |
|
11111111
. 11111111 . 11111111 . 11000000 |
|
|
Subnet Mask: |
255.255.255.192 |
|
First Subnet: |
202.49.18.0 |
|
First Usable Addresses: |
202.49.18.1 |
|
Broadcast Addresses: |
202.49.18.63 |
|
Second Subnet: |
202.49.18.64 |
|
First Usable Addresses: |
202.49.18.65 |
|
Broadcast Addresses: |
202.49.18.127 |
|
Third Subnet: |
202.49.18.128 |
|
First Usable Addresses: |
202.49.18.129 |
|
Broadcast Addresses: |
202.49.18.191 |
|
Fourth Subnet: |
202.49.18.192 |
|
First Usable Addresses: |
202.49.18.193 |
|
Broadcast Addresses: |
202.49.18.255 |
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